Base | Representation |
---|---|
bin | 1010001101001001111001… |
… | …0001101101100000101001 |
3 | 1110201201122110011111102111 |
4 | 2203102132101231200221 |
5 | 2432321313131121022 |
6 | 35510523510402321 |
7 | 2235461365302463 |
oct | 243223621554051 |
9 | 43651573144374 |
10 | 11221110020137 |
11 | 3636934088746 |
12 | 13128870603a1 |
13 | 6351b90995b4 |
14 | 2ab167129133 |
15 | 146d4805e477 |
hex | a349e46d829 |
11221110020137 has 2 divisors, whose sum is σ = 11221110020138. Its totient is φ = 11221110020136.
The previous prime is 11221110020063. The next prime is 11221110020179. The reversal of 11221110020137 is 73102001112211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10896000226281 + 325109793856 = 3300909^2 + 570184^2 .
It is a cyclic number.
It is not a de Polignac number, because 11221110020137 - 27 = 11221110020009 is a prime.
It is not a weakly prime, because it can be changed into another prime (11221110020837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610555010068 + 5610555010069.
It is an arithmetic number, because the mean of its divisors is an integer number (5610555010069).
Almost surely, 211221110020137 is an apocalyptic number.
It is an amenable number.
11221110020137 is a deficient number, since it is larger than the sum of its proper divisors (1).
11221110020137 is an equidigital number, since it uses as much as digits as its factorization.
11221110020137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 22.
Adding to 11221110020137 its reverse (73102001112211), we get a palindrome (84323111132348).
The spelling of 11221110020137 in words is "eleven trillion, two hundred twenty-one billion, one hundred ten million, twenty thousand, one hundred thirty-seven".
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