Base | Representation |
---|---|
bin | 11001100000111000110101… |
… | …010100110011101001111011 |
3 | 112201022021202011200121110111 |
4 | 121200320311110303221323 |
5 | 104201432024304102303 |
6 | 1034353041320525151 |
7 | 32430664252345321 |
oct | 3140706524635173 |
9 | 481267664617414 |
10 | 112211210222203 |
11 | 32832563915024 |
12 | 1070334b3207b7 |
13 | 4a7c6194a5371 |
14 | 1d9d0a1665d11 |
15 | ce8d0edcbb6d |
hex | 660e35533a7b |
112211210222203 has 2 divisors, whose sum is σ = 112211210222204. Its totient is φ = 112211210222202.
The previous prime is 112211210222171. The next prime is 112211210222227. The reversal of 112211210222203 is 302222012112211.
It is a strong prime.
It is an emirp because it is prime and its reverse (302222012112211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112211210222203 - 25 = 112211210222171 is a prime.
It is not a weakly prime, because it can be changed into another prime (112211210222233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56105605111101 + 56105605111102.
It is an arithmetic number, because the mean of its divisors is an integer number (56105605111102).
Almost surely, 2112211210222203 is an apocalyptic number.
112211210222203 is a deficient number, since it is larger than the sum of its proper divisors (1).
112211210222203 is an equidigital number, since it uses as much as digits as its factorization.
112211210222203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 112211210222203 its reverse (302222012112211), we get a palindrome (414433222334414).
The spelling of 112211210222203 in words is "one hundred twelve trillion, two hundred eleven billion, two hundred ten million, two hundred twenty-two thousand, two hundred three".
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