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1122112121131 is a prime number
BaseRepresentation
bin10000010101000011000…
…110000010100100101011
310222021100220220220111001
4100111003012002210223
5121341041200334011
62215254033015431
7144032661441001
oct20250306024453
93867326826431
101122112121131
113a2981047971
121615810b4577
1381a78c25c11
143c44c0b2a71
151e2c6d7a7c1
hex1054318292b

1122112121131 has 2 divisors, whose sum is σ = 1122112121132. Its totient is φ = 1122112121130.

The previous prime is 1122112121077. The next prime is 1122112121153. The reversal of 1122112121131 is 1311212112211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1122112121131 - 211 = 1122112119083 is a prime.

It is a super-2 number, since 2×11221121211312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1122112121099 and 1122112121108.

It is not a weakly prime, because it can be changed into another prime (1122112121531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561056060565 + 561056060566.

It is an arithmetic number, because the mean of its divisors is an integer number (561056060566).

Almost surely, 21122112121131 is an apocalyptic number.

1122112121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122112121131 is an equidigital number, since it uses as much as digits as its factorization.

1122112121131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 19.

Adding to 1122112121131 its reverse (1311212112211), we get a palindrome (2433324233342).

The spelling of 1122112121131 in words is "one trillion, one hundred twenty-two billion, one hundred twelve million, one hundred twenty-one thousand, one hundred thirty-one".