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112211420203 is a prime number
BaseRepresentation
bin110100010000001010…
…0100110010000101011
3101201122012120202121001
41220200110212100223
53314302110421303
6123314344055431
711051463222451
oct1504024462053
9351565522531
10112211420203
114365246a913
12198b7464577
13a7736c967c
145606b949d1
152dbb31d31d
hex1a2052642b

112211420203 has 2 divisors, whose sum is σ = 112211420204. Its totient is φ = 112211420202.

The previous prime is 112211420197. The next prime is 112211420249. The reversal of 112211420203 is 302024112211.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112211420203 is a prime.

It is a super-2 number, since 2×1122114202032 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112211420003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56105710101 + 56105710102.

It is an arithmetic number, because the mean of its divisors is an integer number (56105710102).

Almost surely, 2112211420203 is an apocalyptic number.

112211420203 is a deficient number, since it is larger than the sum of its proper divisors (1).

112211420203 is an equidigital number, since it uses as much as digits as its factorization.

112211420203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 112211420203 its reverse (302024112211), we get a palindrome (414235532414).

The spelling of 112211420203 in words is "one hundred twelve billion, two hundred eleven million, four hundred twenty thousand, two hundred three".