Base | Representation |
---|---|
bin | 1010001101001010010000… |
… | …1111001011100011001011 |
3 | 1110201201220102100000111201 |
4 | 2203102210033023203023 |
5 | 2432322014231120133 |
6 | 35510541442005031 |
7 | 2235464021264422 |
oct | 243224417134313 |
9 | 43651812300451 |
10 | 11221210020043 |
11 | 363698557a0a1 |
12 | 13128b4646777 |
13 | 635203a1003a |
14 | 2ab17651a2b9 |
15 | 146d51c13d7d |
hex | a34a43cb8cb |
11221210020043 has 2 divisors, whose sum is σ = 11221210020044. Its totient is φ = 11221210020042.
The previous prime is 11221210020023. The next prime is 11221210020107. The reversal of 11221210020043 is 34002001212211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11221210020043 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11221210020043.
It is not a weakly prime, because it can be changed into another prime (11221210020023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610605010021 + 5610605010022.
It is an arithmetic number, because the mean of its divisors is an integer number (5610605010022).
Almost surely, 211221210020043 is an apocalyptic number.
11221210020043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11221210020043 is an equidigital number, since it uses as much as digits as its factorization.
11221210020043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11221210020043 its reverse (34002001212211), we get a palindrome (45223211232254).
The spelling of 11221210020043 in words is "eleven trillion, two hundred twenty-one billion, two hundred ten million, twenty thousand, forty-three".
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