Base | Representation |
---|---|
bin | 11001100000111010110001… |
… | …111000101101101010110011 |
3 | 112201022111010210222210220121 |
4 | 121200322301320231222303 |
5 | 104202000314300302101 |
6 | 1034354024532151111 |
7 | 32431100116266151 |
oct | 3140726170555263 |
9 | 481274123883817 |
10 | 112213300009651 |
11 | 32833436508295 |
12 | 10703833168497 |
13 | 4a7c890428999 |
14 | 1d9d21d0143d1 |
15 | ce8dd35c80a1 |
hex | 660eb1e2dab3 |
112213300009651 has 4 divisors (see below), whose sum is σ = 112519058320672. Its totient is φ = 111907541698632.
The previous prime is 112213300009639. The next prime is 112213300009717. The reversal of 112213300009651 is 156900003312211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112213300009651 - 225 = 112213266455219 is a prime.
It is a super-2 number, since 2×1122133000096512 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112213300009051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152879154960 + ... + 152879155693.
It is an arithmetic number, because the mean of its divisors is an integer number (28129764580168).
Almost surely, 2112213300009651 is an apocalyptic number.
112213300009651 is a deficient number, since it is larger than the sum of its proper divisors (305758311021).
112213300009651 is an equidigital number, since it uses as much as digits as its factorization.
112213300009651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 305758311020.
The product of its (nonzero) digits is 9720, while the sum is 34.
The spelling of 112213300009651 in words is "one hundred twelve trillion, two hundred thirteen billion, three hundred million, nine thousand, six hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.097 sec. • engine limits •