Base | Representation |
---|---|
bin | 11001100000111011110011… |
… | …101100001110001101100010 |
3 | 112201022120222202101220221102 |
4 | 121200323303230032031202 |
5 | 104202010044413000310 |
6 | 1034354330251154402 |
7 | 32431136353312226 |
oct | 3140736354161542 |
9 | 481276882356842 |
10 | 112214404031330 |
11 | 3283395271a0a7 |
12 | 10703aa0a45a02 |
13 | 4a7ca08087053 |
14 | 1d9d2c58bc786 |
15 | ce8e4a4a58a5 |
hex | 660ef3b0e362 |
112214404031330 has 16 divisors (see below), whose sum is σ = 202009783075200. Its totient is φ = 44880460319472.
The previous prime is 112214404031273. The next prime is 112214404031369. The reversal of 112214404031330 is 33130404412211.
It is a junction number, because it is equal to n+sod(n) for n = 112214404031293 and 112214404031302.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 662572730 + ... + 662742069.
It is an arithmetic number, because the mean of its divisors is an integer number (12625611442200).
Almost surely, 2112214404031330 is an apocalyptic number.
112214404031330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112214404031330 is a deficient number, since it is larger than the sum of its proper divisors (89795379043870).
112214404031330 is a wasteful number, since it uses less digits than its factorization.
112214404031330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1325323273.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 112214404031330 its reverse (33130404412211), we get a palindrome (145344808443541).
The spelling of 112214404031330 in words is "one hundred twelve trillion, two hundred fourteen billion, four hundred four million, thirty-one thousand, three hundred thirty".
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