Base | Representation |
---|---|
bin | 11001100001000001000111… |
… | …010001001111001111001011 |
3 | 112201100010200210122122022221 |
4 | 121201001013101033033023 |
5 | 104202103231402223313 |
6 | 1034401111445354511 |
7 | 32431430502453565 |
oct | 3141010721171713 |
9 | 481303623578287 |
10 | 112220101211083 |
11 | 3283630661a618 |
12 | 10705010a08a37 |
13 | 4a804054a8428 |
14 | 1d9d6a63c2335 |
15 | ce9180723c8d |
hex | 66104744f3cb |
112220101211083 has 2 divisors, whose sum is σ = 112220101211084. Its totient is φ = 112220101211082.
The previous prime is 112220101211051. The next prime is 112220101211123. The reversal of 112220101211083 is 380112101022211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112220101211083 - 25 = 112220101211051 is a prime.
It is a super-2 number, since 2×1122201012110832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112220101212083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56110050605541 + 56110050605542.
It is an arithmetic number, because the mean of its divisors is an integer number (56110050605542).
Almost surely, 2112220101211083 is an apocalyptic number.
112220101211083 is a deficient number, since it is larger than the sum of its proper divisors (1).
112220101211083 is an equidigital number, since it uses as much as digits as its factorization.
112220101211083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 25.
Adding to 112220101211083 its reverse (380112101022211), we get a palindrome (492332202233294).
The spelling of 112220101211083 in words is "one hundred twelve trillion, two hundred twenty billion, one hundred one million, two hundred eleven thousand, eighty-three".
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