Base | Representation |
---|---|
bin | 10000010101001010001… |
… | …001010111011010101011 |
3 | 10222021200011112210110211 |
4 | 100111022021113122223 |
5 | 121341311442332301 |
6 | 2215313500521551 |
7 | 144035626202611 |
oct | 20251211273253 |
9 | 3867604483424 |
10 | 1122230433451 |
11 | 3a2a31906746 |
12 | 1615b48502b7 |
13 | 81a975ab8ca |
14 | 3c45daad6b1 |
15 | 1e2d244b051 |
hex | 1054a2576ab |
1122230433451 has 2 divisors, whose sum is σ = 1122230433452. Its totient is φ = 1122230433450.
The previous prime is 1122230433383. The next prime is 1122230433469. The reversal of 1122230433451 is 1543340322211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1122230433451 - 27 = 1122230433323 is a prime.
It is a super-2 number, since 2×11222304334512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1122230433491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561115216725 + 561115216726.
It is an arithmetic number, because the mean of its divisors is an integer number (561115216726).
Almost surely, 21122230433451 is an apocalyptic number.
1122230433451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122230433451 is an equidigital number, since it uses as much as digits as its factorization.
1122230433451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1122230433451 its reverse (1543340322211), we get a palindrome (2665570755662).
The spelling of 1122230433451 in words is "one trillion, one hundred twenty-two billion, two hundred thirty million, four hundred thirty-three thousand, four hundred fifty-one".
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