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1122304441403 = 4992249107097
BaseRepresentation
bin10000010101001110100…
…011101011110000111011
310222021212022210210022002
4100111032203223300323
5121341434414111103
62215325103051215
7144040515231335
oct20251643536073
93867768723262
101122304441403
113a2a6a664a42
121616155a0b0b
1381aa9a217b2
143c469856455
151e2d8bb9488
hex1054e8ebc3b

1122304441403 has 4 divisors (see below), whose sum is σ = 1124553549000. Its totient is φ = 1120055333808.

The previous prime is 1122304441327. The next prime is 1122304441429. The reversal of 1122304441403 is 3041444032211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1122304441403 - 220 = 1122303392827 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1122304441303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1124553050 + ... + 1124554047.

It is an arithmetic number, because the mean of its divisors is an integer number (281138387250).

Almost surely, 21122304441403 is an apocalyptic number.

1122304441403 is a deficient number, since it is larger than the sum of its proper divisors (2249107597).

1122304441403 is an equidigital number, since it uses as much as digits as its factorization.

1122304441403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2249107596.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 1122304441403 its reverse (3041444032211), we get a palindrome (4163748473614).

The spelling of 1122304441403 in words is "one trillion, one hundred twenty-two billion, three hundred four million, four hundred forty-one thousand, four hundred three".

Divisors: 1 499 2249107097 1122304441403