Base | Representation |
---|---|
bin | 10000010101001110111… |
… | …101111101110111101011 |
3 | 10222021212210202211110201 |
4 | 100111032331331313223 |
5 | 121341443200100212 |
6 | 2215325510453031 |
7 | 144040630625455 |
oct | 20251675756753 |
9 | 3867783684421 |
10 | 1122311331307 |
11 | 3a2a73540481 |
12 | 161617964177 |
13 | 81aab29486a |
14 | 3c46a72b2d5 |
15 | 1e2d95cab57 |
hex | 1054ef7ddeb |
1122311331307 has 2 divisors, whose sum is σ = 1122311331308. Its totient is φ = 1122311331306.
The previous prime is 1122311331263. The next prime is 1122311331311. The reversal of 1122311331307 is 7031331132211.
It is a strong prime.
It is an emirp because it is prime and its reverse (7031331132211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1122311331307 - 215 = 1122311298539 is a prime.
It is not a weakly prime, because it can be changed into another prime (1122311331347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561155665653 + 561155665654.
It is an arithmetic number, because the mean of its divisors is an integer number (561155665654).
Almost surely, 21122311331307 is an apocalyptic number.
1122311331307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122311331307 is an equidigital number, since it uses as much as digits as its factorization.
1122311331307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 1122311331307 its reverse (7031331132211), we get a palindrome (8153642463518).
The spelling of 1122311331307 in words is "one trillion, one hundred twenty-two billion, three hundred eleven million, three hundred thirty-one thousand, three hundred seven".
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