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1122330524473 is a prime number
BaseRepresentation
bin10000010101010000000…
…111001011101100111001
310222021221010212221112201
4100111100013023230321
5121342013103240343
62215331434110201
7144041253024304
oct20252007135471
93867833787481
101122330524473
113a2a8335a5a4
1216162227b361
1381ab2254972
143c46d0c5b3b
151e2db11c94d
hex105501cbb39

1122330524473 has 2 divisors, whose sum is σ = 1122330524474. Its totient is φ = 1122330524472.

The previous prime is 1122330524437. The next prime is 1122330524527. The reversal of 1122330524473 is 3744250332211.

Together with previous prime (1122330524437) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1004068129024 + 118262395449 = 1002032^2 + 343893^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1122330524473 is a prime.

It is not a weakly prime, because it can be changed into another prime (1122330524173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561165262236 + 561165262237.

It is an arithmetic number, because the mean of its divisors is an integer number (561165262237).

Almost surely, 21122330524473 is an apocalyptic number.

It is an amenable number.

1122330524473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122330524473 is an equidigital number, since it uses as much as digits as its factorization.

1122330524473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 37.

Adding to 1122330524473 its reverse (3744250332211), we get a palindrome (4866580856684).

The spelling of 1122330524473 in words is "one trillion, one hundred twenty-two billion, three hundred thirty million, five hundred twenty-four thousand, four hundred seventy-three".