Base | Representation |
---|---|
bin | 10000010101011100010… |
… | …000101001101011000001 |
3 | 10222022110100101111110011 |
4 | 100111130100221223001 |
5 | 121342422242124441 |
6 | 2215403554304521 |
7 | 144046306253515 |
oct | 20253420515301 |
9 | 3868410344404 |
10 | 1122534333121 |
11 | 3a3078403aa3 |
12 | 16167a588141 |
13 | 81b155436b6 |
14 | 3c48c1ba145 |
15 | 1e2ede7a581 |
hex | 1055c429ac1 |
1122534333121 has 2 divisors, whose sum is σ = 1122534333122. Its totient is φ = 1122534333120.
The previous prime is 1122534333013. The next prime is 1122534333139. The reversal of 1122534333121 is 1213334352211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1051065796225 + 71468536896 = 1025215^2 + 267336^2 .
It is a cyclic number.
It is not a de Polignac number, because 1122534333121 - 27 = 1122534332993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1122534337121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561267166560 + 561267166561.
It is an arithmetic number, because the mean of its divisors is an integer number (561267166561).
Almost surely, 21122534333121 is an apocalyptic number.
It is an amenable number.
1122534333121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122534333121 is an equidigital number, since it uses as much as digits as its factorization.
1122534333121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12960, while the sum is 31.
Adding to 1122534333121 its reverse (1213334352211), we get a palindrome (2335868685332).
The spelling of 1122534333121 in words is "one trillion, one hundred twenty-two billion, five hundred thirty-four million, three hundred thirty-three thousand, one hundred twenty-one".
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