Search a number
-
+
11230004443 = 71604286349
BaseRepresentation
bin10100111010101110…
…00100010011011011
31001222122020100000111
422131113010103123
5140444340120233
65054201545151
7545201314510
oct123527042333
931878210014
1011230004443
114843054609
122214aa51b7
13109c788958
14787663307
1545ad73acd
hex29d5c44db

11230004443 has 4 divisors (see below), whose sum is σ = 12834290800. Its totient is φ = 9625718088.

The previous prime is 11230004441. The next prime is 11230004459. The reversal of 11230004443 is 34440003211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34440003211 = 56361172297.

It is not a de Polignac number, because 11230004443 - 21 = 11230004441 is a prime.

It is a super-2 number, since 2×112300044432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11230004441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 802143168 + ... + 802143181.

It is an arithmetic number, because the mean of its divisors is an integer number (3208572700).

Almost surely, 211230004443 is an apocalyptic number.

11230004443 is a deficient number, since it is larger than the sum of its proper divisors (1604286357).

11230004443 is an equidigital number, since it uses as much as digits as its factorization.

11230004443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1604286356.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 11230004443 its reverse (34440003211), we get a palindrome (45670007654).

The spelling of 11230004443 in words is "eleven billion, two hundred thirty million, four thousand, four hundred forty-three".

Divisors: 1 7 1604286349 11230004443