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112300303147 is a prime number
BaseRepresentation
bin110100010010110011…
…1101010001100101011
3101201212101211111001221
41220211213222030223
53314442334200042
6123331241122511
711053622553424
oct1504547521453
9351771744057
10112300303147
114369865899a
1219921189437
13a788c4a026
1456148d064b
152dc4028d67
hex1a259ea32b

112300303147 has 2 divisors, whose sum is σ = 112300303148. Its totient is φ = 112300303146.

The previous prime is 112300303139. The next prime is 112300303169. The reversal of 112300303147 is 741303003211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 112300303147 - 23 = 112300303139 is a prime.

It is a super-2 number, since 2×1123003031472 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112300303747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56150151573 + 56150151574.

It is an arithmetic number, because the mean of its divisors is an integer number (56150151574).

Almost surely, 2112300303147 is an apocalyptic number.

112300303147 is a deficient number, since it is larger than the sum of its proper divisors (1).

112300303147 is an equidigital number, since it uses as much as digits as its factorization.

112300303147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 112300303147 its reverse (741303003211), we get a palindrome (853603306358).

The spelling of 112300303147 in words is "one hundred twelve billion, three hundred million, three hundred three thousand, one hundred forty-seven".