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1123113303331 is a prime number
BaseRepresentation
bin10000010101111110110…
…001001111110100100011
310222100221200211020021021
4100111332301033310203
5121400114001201311
62215541235510311
7144066536364355
oct20257661176443
93870850736237
101123113303331
113a33451a8978
12161800458397
1381ba8488216
143c50504b0d5
151e334be2171
hex1057ec4fd23

1123113303331 has 2 divisors, whose sum is σ = 1123113303332. Its totient is φ = 1123113303330.

The previous prime is 1123113303313. The next prime is 1123113303337. The reversal of 1123113303331 is 1333033113211.

Together with previous prime (1123113303313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1123113303331 - 27 = 1123113303203 is a prime.

It is a super-2 number, since 2×11231133033312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1123113303296 and 1123113303305.

It is not a weakly prime, because it can be changed into another prime (1123113303337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561556651665 + 561556651666.

It is an arithmetic number, because the mean of its divisors is an integer number (561556651666).

Almost surely, 21123113303331 is an apocalyptic number.

1123113303331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123113303331 is an equidigital number, since it uses as much as digits as its factorization.

1123113303331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1123113303331 its reverse (1333033113211), we get a palindrome (2456146416542).

The spelling of 1123113303331 in words is "one trillion, one hundred twenty-three billion, one hundred thirteen million, three hundred three thousand, three hundred thirty-one".