11231221013017 has 2 divisors, whose sum is σ = 11231221013018. Its totient is φ = 11231221013016.

The previous prime is 11231221012969. The next prime is 11231221013029. The reversal of 11231221013017 is 71031012213211.

11231221013017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10491794722816 + 739426290201 = 3239104^2 + 859899^2 .

It is an emirp because it is prime and its reverse (71031012213211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11231221013017 - 2¹⁹ = 11231220488729 is a prime.

It is a super-2 number, since 2×11231221013017² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11231221012982 and 11231221013000.

It is not a weakly prime, because it can be changed into another prime (11231221013057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615610506508 + 5615610506509.

It is an arithmetic number, because the mean of its divisors is an integer number (5615610506509).

Almost surely, 2^{11231221013017} is an apocalyptic number.

It is an amenable number.

11231221013017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11231221013017 is an equidigital number, since it uses as much as digits as its factorization.

11231221013017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 11231221013017 its reverse (71031012213211), we get a palindrome (82262233226228).

The spelling of 11231221013017 in words is "eleven trillion, two hundred thirty-one billion, two hundred twenty-one million, thirteen thousand, seventeen".