Base | Representation |
---|---|
bin | 110100010011001100… |
… | …0011110011110111001 |
3 | 101201220021220122100111 |
4 | 1220212120132132321 |
5 | 3320004123201332 |
6 | 123332415304321 |
7 | 11054136412603 |
oct | 1504630363671 |
9 | 351807818314 |
10 | 112313100217 |
11 | 436a48a958a |
12 | 1992551b0a1 |
13 | a78b7aaa66 |
14 | 56164a2173 |
15 | 2dc5205947 |
hex | 1a2661e7b9 |
112313100217 has 2 divisors, whose sum is σ = 112313100218. Its totient is φ = 112313100216.
The previous prime is 112313100203. The next prime is 112313100281. The reversal of 112313100217 is 712001313211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67716530176 + 44596570041 = 260224^2 + 211179^2 .
It is a cyclic number.
It is not a de Polignac number, because 112313100217 - 211 = 112313098169 is a prime.
It is a super-2 number, since 2×1123131002172 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112313130217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56156550108 + 56156550109.
It is an arithmetic number, because the mean of its divisors is an integer number (56156550109).
Almost surely, 2112313100217 is an apocalyptic number.
It is an amenable number.
112313100217 is a deficient number, since it is larger than the sum of its proper divisors (1).
112313100217 is an equidigital number, since it uses as much as digits as its factorization.
112313100217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 112313100217 its reverse (712001313211), we get a palindrome (824314413428).
The spelling of 112313100217 in words is "one hundred twelve billion, three hundred thirteen million, one hundred thousand, two hundred seventeen".
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