11231421111121 has 2 divisors, whose sum is σ = 11231421111122. Its totient is φ = 11231421111120.

The previous prime is 11231421111107. The next prime is 11231421111217. The reversal of 11231421111121 is 12111112413211.

11231421111121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a m-pointer prime, because the next prime (11231421111217) can be obtained adding 11231421111121 to its product of digits (96).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10936506947521 + 294914163600 = 3307039^2 + 543060^2 .

It is a cyclic number.

It is not a de Polignac number, because 11231421111121 - 2²³ = 11231412722513 is a prime.

It is a super-2 number, since 2×11231421111121² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11231421111092 and 11231421111101.

It is not a weakly prime, because it can be changed into another prime (11231421111821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615710555560 + 5615710555561.

It is an arithmetic number, because the mean of its divisors is an integer number (5615710555561).

Almost surely, 2^{11231421111121} is an apocalyptic number.

It is an amenable number.

11231421111121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11231421111121 is an equidigital number, since it uses as much as digits as its factorization.

11231421111121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 22.

Adding to 11231421111121 its reverse (12111112413211), we get a palindrome (23342533524332).

The spelling of 11231421111121 in words is "eleven trillion, two hundred thirty-one billion, four hundred twenty-one million, one hundred eleven thousand, one hundred twenty-one".