Base | Representation |
---|---|
bin | 11001100010011000110111… |
… | …110011011100101111001010 |
3 | 112201200010220211200010102011 |
4 | 121202120313303130233022 |
5 | 104210124222220234310 |
6 | 1034512254045330134 |
7 | 32441304552611311 |
oct | 3142306763345712 |
9 | 481603824603364 |
10 | 112314331024330 |
11 | 3287227091aa36 |
12 | 1071b32a26694a |
13 | 4a89271714386 |
14 | 1da4084d77278 |
15 | ceb8480bd78a |
hex | 662637cdcbca |
112314331024330 has 32 divisors (see below), whose sum is σ = 202291053048000. Its totient is φ = 44897903711232.
The previous prime is 112314331024297. The next prime is 112314331024369. The reversal of 112314331024330 is 33420133413211.
It is a super-2 number, since 2×1123143310243302 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112314331024292 and 112314331024301.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 145390641 + ... + 146161099.
It is an arithmetic number, because the mean of its divisors is an integer number (6321595407750).
Almost surely, 2112314331024330 is an apocalyptic number.
112314331024330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112314331024330 is a deficient number, since it is larger than the sum of its proper divisors (89976722023670).
112314331024330 is a wasteful number, since it uses less digits than its factorization.
112314331024330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779478.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 112314331024330 its reverse (33420133413211), we get a palindrome (145734464437541).
The spelling of 112314331024330 in words is "one hundred twelve trillion, three hundred fourteen billion, three hundred thirty-one million, twenty-four thousand, three hundred thirty".
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