Base | Representation |
---|---|
bin | 10000010110000000100… |
… | …011110011100100000011 |
3 | 10222101000210022221210201 |
4 | 100112000203303210003 |
5 | 121400144143143042 |
6 | 2215544231310031 |
7 | 144100352551642 |
oct | 20260043634403 |
9 | 3871023287721 |
10 | 1123143334147 |
11 | 3a336014a52a |
12 | 16180a51b317 |
13 | 81bb1771233 |
14 | 3c509027359 |
15 | 1e3376751b7 |
hex | 105808f3903 |
1123143334147 has 2 divisors, whose sum is σ = 1123143334148. Its totient is φ = 1123143334146.
The previous prime is 1123143334141. The next prime is 1123143334177. The reversal of 1123143334147 is 7414333413211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1123143334147 is a prime.
It is a super-2 number, since 2×11231433341472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1123143334141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561571667073 + 561571667074.
It is an arithmetic number, because the mean of its divisors is an integer number (561571667074).
Almost surely, 21123143334147 is an apocalyptic number.
1123143334147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123143334147 is an equidigital number, since it uses as much as digits as its factorization.
1123143334147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72576, while the sum is 37.
Adding to 1123143334147 its reverse (7414333413211), we get a palindrome (8537476747358).
The spelling of 1123143334147 in words is "one trillion, one hundred twenty-three billion, one hundred forty-three million, three hundred thirty-four thousand, one hundred forty-seven".
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