Base | Representation |
---|---|
bin | 11001100010011110010101… |
… | …101100110110111000011011 |
3 | 112201200201001221200010221210 |
4 | 121202132111230312320123 |
5 | 104210223233014301021 |
6 | 1034515104350234203 |
7 | 32441603203405644 |
oct | 3142362554667033 |
9 | 481621057603853 |
10 | 112320201322011 |
11 | 32874803512521 |
12 | 107204a81b5963 |
13 | 4a89998969cb7 |
14 | 1da44808626cb |
15 | ceba8d635e76 |
hex | 662795b36e1b |
112320201322011 has 16 divisors (see below), whose sum is σ = 150753435533568. Its totient is φ = 74383559724000.
The previous prime is 112320201322003. The next prime is 112320201322033. The reversal of 112320201322011 is 110223102023211.
It is not a de Polignac number, because 112320201322011 - 23 = 112320201322003 is a prime.
It is a super-4 number, since 4×1123202013220114 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (112320201322711) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51170005 + ... + 53319881.
It is an arithmetic number, because the mean of its divisors is an integer number (9422089720848).
Almost surely, 2112320201322011 is an apocalyptic number.
112320201322011 is a deficient number, since it is larger than the sum of its proper divisors (38433234211557).
112320201322011 is a wasteful number, since it uses less digits than its factorization.
112320201322011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2265362.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 112320201322011 its reverse (110223102023211), we get a palindrome (222543303345222).
The spelling of 112320201322011 in words is "one hundred twelve trillion, three hundred twenty billion, two hundred one million, three hundred twenty-two thousand, eleven".
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