Base | Representation |
---|---|
bin | 1010001101110010111010… |
… | …0110000100010010010011 |
3 | 1110202210001211122220021101 |
4 | 2203130232212010102103 |
5 | 2433011341012210003 |
6 | 35515544254405231 |
7 | 2236331302002031 |
oct | 243345646042223 |
9 | 43683054586241 |
10 | 11232121210003 |
11 | 3640574669661 |
12 | 1314a3a800817 |
13 | 636252411265 |
14 | 2ab8cd6ad551 |
15 | 14728eaae11d |
hex | a372e984493 |
11232121210003 has 2 divisors, whose sum is σ = 11232121210004. Its totient is φ = 11232121210002.
The previous prime is 11232121209931. The next prime is 11232121210081. The reversal of 11232121210003 is 30001212123211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11232121210003 is a prime.
It is not a weakly prime, because it can be changed into another prime (11232121216003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5616060605001 + 5616060605002.
It is an arithmetic number, because the mean of its divisors is an integer number (5616060605002).
Almost surely, 211232121210003 is an apocalyptic number.
11232121210003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11232121210003 is an equidigital number, since it uses as much as digits as its factorization.
11232121210003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11232121210003 its reverse (30001212123211), we get a palindrome (41233333333214).
The spelling of 11232121210003 in words is "eleven trillion, two hundred thirty-two billion, one hundred twenty-one million, two hundred ten thousand, three".
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