Base | Representation |
---|---|
bin | 10000010110000101001… |
… | …001000001101011010011 |
3 | 10222101020010222011010121 |
4 | 100112011021001223103 |
5 | 121400323332401042 |
6 | 2220000015011111 |
7 | 144102305113033 |
oct | 20260511015323 |
9 | 3871203864117 |
10 | 1123220200147 |
11 | 3a339a580051 |
12 | 161830209a97 |
13 | 81bc4674c86 |
14 | 3c5153158c3 |
15 | 1e33e2aa367 |
hex | 10585241ad3 |
1123220200147 has 2 divisors, whose sum is σ = 1123220200148. Its totient is φ = 1123220200146.
The previous prime is 1123220200093. The next prime is 1123220200253. The reversal of 1123220200147 is 7410020223211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1123220200147 - 211 = 1123220198099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1123220230147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561610100073 + 561610100074.
It is an arithmetic number, because the mean of its divisors is an integer number (561610100074).
Almost surely, 21123220200147 is an apocalyptic number.
1123220200147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123220200147 is an equidigital number, since it uses as much as digits as its factorization.
1123220200147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 1123220200147 its reverse (7410020223211), we get a palindrome (8533240423358).
The spelling of 1123220200147 in words is "one trillion, one hundred twenty-three billion, two hundred twenty million, two hundred thousand, one hundred forty-seven".
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