11233001300121 has 24 divisors (see below), whose sum is σ = 16978386489480. Its totient is φ = 7148794288896.

The previous prime is 11233001300099. The next prime is 11233001300197. The reversal of 11233001300121 is 12100310033211.

11233001300121 is a `hidden beast` number, since 1 + 12 + 330 + 0 + 1 + 300 + 1 + 21 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 1943849408400 + 9289151891721 = 1394220^2 + 3047811^2 .

It is not a de Polignac number, because 11233001300121 - 2¹⁵ = 11233001267353 is a prime.

It is a super-2 number, since 2×11233001300121² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11233001300094 and 11233001300103.

It is not an unprimeable number, because it can be changed into a prime (11233001300221) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 318215716 + ... + 318251013.

It is an arithmetic number, because the mean of its divisors is an integer number (707432770395).

Almost surely, 2^{11233001300121} is an apocalyptic number.

It is an amenable number.

11233001300121 is a deficient number, since it is larger than the sum of its proper divisors (5745385189359).

11233001300121 is a wasteful number, since it uses less digits than its factorization.

11233001300121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 636466825 (or 636466822 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 11233001300121 its reverse (12100310033211), we get a palindrome (23333311333332).

The spelling of 11233001300121 in words is "eleven trillion, two hundred thirty-three billion, one million, three hundred thousand, one hundred twenty-one".