Base | Representation |
---|---|
bin | 10000010110001010100… |
… | …011110010100010110011 |
3 | 10222101110111000110012202 |
4 | 100112022203302202303 |
5 | 121401020120232011 |
6 | 2220013023213415 |
7 | 144104460553301 |
oct | 20261243624263 |
9 | 3871414013182 |
10 | 1123311102131 |
11 | 3a3436918059 |
12 | 16185674726b |
13 | 81c0a45162a |
14 | 3c523419271 |
15 | 1e34726423b |
hex | 1058a8f28b3 |
1123311102131 has 2 divisors, whose sum is σ = 1123311102132. Its totient is φ = 1123311102130.
The previous prime is 1123311102127. The next prime is 1123311102163. The reversal of 1123311102131 is 1312011133211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1123311102131 - 22 = 1123311102127 is a prime.
It is a super-2 number, since 2×11233111021312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1123361102131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561655551065 + 561655551066.
It is an arithmetic number, because the mean of its divisors is an integer number (561655551066).
Almost surely, 21123311102131 is an apocalyptic number.
1123311102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123311102131 is an equidigital number, since it uses as much as digits as its factorization.
1123311102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1123311102131 its reverse (1312011133211), we get a palindrome (2435322235342).
The spelling of 1123311102131 in words is "one trillion, one hundred twenty-three billion, three hundred eleven million, one hundred two thousand, one hundred thirty-one".
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