11233212433 has 4 divisors (see below), whose sum is σ = 11824434160. Its totient is φ = 10641990708.

The previous prime is 11233212413. The next prime is 11233212439. The reversal of 11233212433 is 33421233211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11233212433 - 2⁹ = 11233211921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11233212398 and 11233212407.

It is not an unprimeable number, because it can be changed into a prime (11233212439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 295610835 + ... + 295610872.

It is an arithmetic number, because the mean of its divisors is an integer number (2956108540).

Almost surely, 2^11233212433 is an apocalyptic number.

It is an amenable number.

11233212433 is a deficient number, since it is larger than the sum of its proper divisors (591221727).

11233212433 is an equidigital number, since it uses as much as digits as its factorization.

11233212433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 591221726.

The product of its digits is 2592, while the sum is 25.

Adding to 11233212433 its reverse (33421233211), we get a palindrome (44654445644).

The spelling of 11233212433 in words is "eleven billion, two hundred thirty-three million, two hundred twelve thousand, four hundred thirty-three".