11233301013001 has 4 divisors (see below), whose sum is σ = 11445250088772. Its totient is φ = 11021351937232.

The previous prime is 11233301012971. The next prime is 11233301013013. The reversal of 11233301013001 is 10031010333211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6609403407376 + 4623897605625 = 2570876^2 + 2150325^2 .

It is a cyclic number.

It is not a de Polignac number, because 11233301013001 - 2¹⁵ = 11233300980233 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11233301013001.

It is not an unprimeable number, because it can be changed into a prime (11233301013101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105974537806 + ... + 105974537911.

It is an arithmetic number, because the mean of its divisors is an integer number (2861312522193).

Almost surely, 2^{11233301013001} is an apocalyptic number.

It is an amenable number.

11233301013001 is a deficient number, since it is larger than the sum of its proper divisors (211949075771).

11233301013001 is an equidigital number, since it uses as much as digits as its factorization.

11233301013001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 211949075770.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11233301013001 its reverse (10031010333211), we get a palindrome (21264311346212).

The spelling of 11233301013001 in words is "eleven trillion, two hundred thirty-three billion, three hundred one million, thirteen thousand, one".