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1123400040001 = 2447459092783
BaseRepresentation
bin10000010110001111110…
…111000011111001000001
310222101200200100222000221
4100112033313003321001
5121401210402240001
62220025521343041
7144106620533341
oct20261767037101
93871620328027
101123400040001
113a3482043428
12161880497a81
1381c229c0ca5
143c53116ad21
151e34ee811a1
hex1058fdc3e41

1123400040001 has 4 divisors (see below), whose sum is σ = 1123859135232. Its totient is φ = 1122940944772.

The previous prime is 1123400039989. The next prime is 1123400040011. The reversal of 1123400040001 is 1000400043211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1123400040001 - 25 = 1123400039969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1123400040011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229543945 + ... + 229548838.

It is an arithmetic number, because the mean of its divisors is an integer number (280964783808).

Almost surely, 21123400040001 is an apocalyptic number.

It is an amenable number.

1123400040001 is a deficient number, since it is larger than the sum of its proper divisors (459095231).

1123400040001 is an equidigital number, since it uses as much as digits as its factorization.

1123400040001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 459095230.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 1123400040001 its reverse (1000400043211), we get a palindrome (2123800083212).

The spelling of 1123400040001 in words is "one trillion, one hundred twenty-three billion, four hundred million, forty thousand, one".

Divisors: 1 2447 459092783 1123400040001