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11234001433 = 31362387143
BaseRepresentation
bin10100111011001100…
…10100001000011001
31001222220202101212011
422131212110020121
5141001401021213
65054423345521
7545250302524
oct123546241031
931886671764
1011234001433
114845334606
1222162b22a1
1310a0558035
14787dc3bbb
1545b3b303d
hex29d994219

11234001433 has 4 divisors (see below), whose sum is σ = 11596388608. Its totient is φ = 10871614260.

The previous prime is 11234001431. The next prime is 11234001439. The reversal of 11234001433 is 33410043211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11234001433 - 21 = 11234001431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11234001431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181193541 + ... + 181193602.

It is an arithmetic number, because the mean of its divisors is an integer number (2899097152).

Almost surely, 211234001433 is an apocalyptic number.

It is an amenable number.

11234001433 is a deficient number, since it is larger than the sum of its proper divisors (362387175).

11234001433 is an equidigital number, since it uses as much as digits as its factorization.

11234001433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 362387174.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 11234001433 its reverse (33410043211), we get a palindrome (44644044644).

The spelling of 11234001433 in words is "eleven billion, two hundred thirty-four million, one thousand, four hundred thirty-three".

Divisors: 1 31 362387143 11234001433