Base | Representation |
---|---|
bin | 10000010110010000011… |
… | …101011111011011000001 |
3 | 10222101201101022210021221 |
4 | 100112100131133123001 |
5 | 121401220442123431 |
6 | 2220030521315041 |
7 | 144110102262322 |
oct | 20262035373301 |
9 | 3871641283257 |
10 | 1123410114241 |
11 | 3a34877a4348 |
12 | 161883935a81 |
13 | 81c24b0a58c |
14 | 3c532630449 |
15 | 1e350cc1111 |
hex | 1059075f6c1 |
1123410114241 has 8 divisors (see below), whose sum is σ = 1124957744960. Its totient is φ = 1121862652848.
The previous prime is 1123410114221. The next prime is 1123410114271. The reversal of 1123410114241 is 1424110143211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1123410114241 - 25 = 1123410114209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1123410114221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19152340 + ... + 19210906.
It is an arithmetic number, because the mean of its divisors is an integer number (140619718120).
Almost surely, 21123410114241 is an apocalyptic number.
It is an amenable number.
1123410114241 is a deficient number, since it is larger than the sum of its proper divisors (1547630719).
1123410114241 is an equidigital number, since it uses as much as digits as its factorization.
1123410114241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84663.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1123410114241 its reverse (1424110143211), we get a palindrome (2547520257452).
The spelling of 1123410114241 in words is "one trillion, one hundred twenty-three billion, four hundred ten million, one hundred fourteen thousand, two hundred forty-one".
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