1123411214011 has 2 divisors, whose sum is σ = 1123411214012. Its totient is φ = 1123411214010.

The previous prime is 1123411213817. The next prime is 1123411214017. The reversal of 1123411214011 is 1104121143211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1123411214011 is a prime.

It is not a weakly prime, because it can be changed into another prime (1123411214017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561705607005 + 561705607006.

It is an arithmetic number, because the mean of its divisors is an integer number (561705607006).

Almost surely, 2^{1123411214011} is an apocalyptic number.

1123411214011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123411214011 is an equidigital number, since it uses as much as digits as its factorization.

1123411214011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 1123411214011 its reverse (1104121143211), we get a palindrome (2227532357222).

The spelling of 1123411214011 in words is "one trillion, one hundred twenty-three billion, four hundred eleven million, two hundred fourteen thousand, eleven".