1123414103041 has 2 divisors, whose sum is σ = 1123414103042. Its totient is φ = 1123414103040.

The previous prime is 1123414102999. The next prime is 1123414103087. The reversal of 1123414103041 is 1403014143211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 984452902416 + 138961200625 = 992196^2 + 372775^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1123414103041 is a prime.

It is a super-2 number, since 2×1123414103041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1123414102997 and 1123414103015.

It is not a weakly prime, because it can be changed into another prime (1123414103941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561707051520 + 561707051521.

It is an arithmetic number, because the mean of its divisors is an integer number (561707051521).

Almost surely, 2^{1123414103041} is an apocalyptic number.

It is an amenable number.

1123414103041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123414103041 is an equidigital number, since it uses as much as digits as its factorization.

1123414103041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1123414103041 its reverse (1403014143211), we get a palindrome (2526428246252).

The spelling of 1123414103041 in words is "one trillion, one hundred twenty-three billion, four hundred fourteen million, one hundred three thousand, forty-one".