Base | Representation |
---|---|
bin | 110100010100000010… |
… | …1100101010111110011 |
3 | 101201222021201202210122 |
4 | 1220220011211113303 |
5 | 3320033433432011 |
6 | 123335320320455 |
7 | 11054634466241 |
oct | 1505005452763 |
9 | 351867652718 |
10 | 112341702131 |
11 | 43709a6462a |
12 | 1993301312b |
13 | a7946b3579 |
14 | 561a1c9791 |
15 | 2dc79a53db |
hex | 1a281655f3 |
112341702131 has 2 divisors, whose sum is σ = 112341702132. Its totient is φ = 112341702130.
The previous prime is 112341702079. The next prime is 112341702149. The reversal of 112341702131 is 131207143211.
It is a strong prime.
It is an emirp because it is prime and its reverse (131207143211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112341702131 - 210 = 112341701107 is a prime.
It is a super-2 number, since 2×1123417021312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 112341702131.
It is not a weakly prime, because it can be changed into another prime (112341705131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56170851065 + 56170851066.
It is an arithmetic number, because the mean of its divisors is an integer number (56170851066).
Almost surely, 2112341702131 is an apocalyptic number.
112341702131 is a deficient number, since it is larger than the sum of its proper divisors (1).
112341702131 is an equidigital number, since it uses as much as digits as its factorization.
112341702131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 112341702131 its reverse (131207143211), we get a palindrome (243548845342).
The spelling of 112341702131 in words is "one hundred twelve billion, three hundred forty-one million, seven hundred two thousand, one hundred thirty-one".
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