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112342234343441 is a prime number
BaseRepresentation
bin11001100010110010110110…
…111110001010100000010001
3112201202210221110200121022112
4121202302312332022200101
5104211103343442442231
61034533150542315105
732443313203116014
oct3142626676124021
9481683843617275
10112342234343441
113288308a592643
1210724816b88a95
134a8ba9a5b129b
141da5570b5b37b
15cec42cad892b
hex662cb6f8a811

112342234343441 has 2 divisors, whose sum is σ = 112342234343442. Its totient is φ = 112342234343440.

The previous prime is 112342234343429. The next prime is 112342234343489. The reversal of 112342234343441 is 144343432243211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103739745343441 + 8602489000000 = 10185271^2 + 2933000^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112342234343441 is a prime.

It is a super-2 number, since 2×1123422343434412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112342234345441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56171117171720 + 56171117171721.

It is an arithmetic number, because the mean of its divisors is an integer number (56171117171721).

Almost surely, 2112342234343441 is an apocalyptic number.

It is an amenable number.

112342234343441 is a deficient number, since it is larger than the sum of its proper divisors (1).

112342234343441 is an equidigital number, since it uses as much as digits as its factorization.

112342234343441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 663552, while the sum is 41.

Adding to 112342234343441 its reverse (144343432243211), we get a palindrome (256685666586652).

The spelling of 112342234343441 in words is "one hundred twelve trillion, three hundred forty-two billion, two hundred thirty-four million, three hundred forty-three thousand, four hundred forty-one".