1123424433 has 12 divisors (see below), whose sum is σ = 1623040848. Its totient is φ = 748803480.

The previous prime is 1123424383. The next prime is 1123424437. The reversal of 1123424433 is 3344243211.

It is not a de Polignac number, because 1123424433 - 2⁹ = 1123423921 is a prime.

It is a super-2 number, since 2×1123424433² = 2524164913322742978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1123424397 and 1123424406.

It is not an unprimeable number, because it can be changed into a prime (1123424437) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 57466 + ... + 74492.

It is an arithmetic number, because the mean of its divisors is an integer number (135253404).

Almost surely, 2^1123424433 is an apocalyptic number.

It is an amenable number.

1123424433 is a deficient number, since it is larger than the sum of its proper divisors (499616415).

1123424433 is a wasteful number, since it uses less digits than its factorization.

1123424433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24364 (or 24361 counting only the distinct ones).

The product of its digits is 6912, while the sum is 27.

The square root of 1123424433 is about 33517.5242671651. The cubic root of 1123424433 is about 1039.5561570692.

Adding to 1123424433 its reverse (3344243211), we get a palindrome (4467667644).

The spelling of 1123424433 in words is "one billion, one hundred twenty-three million, four hundred twenty-four thousand, four hundred thirty-three".