Base | Representation |
---|---|
bin | 10100111011001110… |
… | …11110111011010001 |
3 | 1001222221022222002211 |
4 | 22131213132323101 |
5 | 141001440322133 |
6 | 5054434112121 |
7 | 545253016642 |
oct | 123547367321 |
9 | 31887288084 |
10 | 11234307793 |
11 | 48455237a5 |
12 | 221641b641 |
13 | 10a0634607 |
14 | 7880636c9 |
15 | 45b423bcd |
hex | 29d9deed1 |
11234307793 has 2 divisors, whose sum is σ = 11234307794. Its totient is φ = 11234307792.
The previous prime is 11234307781. The next prime is 11234307893. The reversal of 11234307793 is 39770343211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9657582529 + 1576725264 = 98273^2 + 39708^2 .
It is a cyclic number.
It is not a de Polignac number, because 11234307793 - 233 = 2644373201 is a prime.
It is not a weakly prime, because it can be changed into another prime (11234307893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617153896 + 5617153897.
It is an arithmetic number, because the mean of its divisors is an integer number (5617153897).
Almost surely, 211234307793 is an apocalyptic number.
It is an amenable number.
11234307793 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234307793 is an equidigital number, since it uses as much as digits as its factorization.
11234307793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 95256, while the sum is 40.
The spelling of 11234307793 in words is "eleven billion, two hundred thirty-four million, three hundred seven thousand, seven hundred ninety-three".
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