1123433011993 has 2 divisors, whose sum is σ = 1123433011994. Its totient is φ = 1123433011992.

The previous prime is 1123433011973. The next prime is 1123433012057. The reversal of 1123433011993 is 3991103343211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 932698172169 + 190734839824 = 965763^2 + 436732^2 .

It is an emirp because it is prime and its reverse (3991103343211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1123433011993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1123433011973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561716505996 + 561716505997.

It is an arithmetic number, because the mean of its divisors is an integer number (561716505997).

Almost surely, 2^{1123433011993} is an apocalyptic number.

It is an amenable number.

1123433011993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123433011993 is an equidigital number, since it uses as much as digits as its factorization.

1123433011993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52488, while the sum is 40.

The spelling of 1123433011993 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-three million, eleven thousand, nine hundred ninety-three".