Base | Representation |
---|---|
bin | 10000010110010001110… |
… | …101101010111101111001 |
3 | 10222101202222211012102121 |
4 | 100112101311222331321 |
5 | 121401242401331301 |
6 | 2220033105001241 |
7 | 144110502616642 |
oct | 20262165527571 |
9 | 3871688735377 |
10 | 1123433230201 |
11 | 3a3499852747 |
12 | 16188b623221 |
13 | 81c29842069 |
14 | 3c53572a6c9 |
15 | 1e352d3a3a1 |
hex | 10591d6af79 |
1123433230201 has 2 divisors, whose sum is σ = 1123433230202. Its totient is φ = 1123433230200.
The previous prime is 1123433229991. The next prime is 1123433230207. The reversal of 1123433230201 is 1020323343211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1044739515625 + 78693714576 = 1022125^2 + 280524^2 .
It is a cyclic number.
It is not a de Polignac number, because 1123433230201 - 233 = 1114843295609 is a prime.
It is not a weakly prime, because it can be changed into another prime (1123433230207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561716615100 + 561716615101.
It is an arithmetic number, because the mean of its divisors is an integer number (561716615101).
Almost surely, 21123433230201 is an apocalyptic number.
It is an amenable number.
1123433230201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123433230201 is an equidigital number, since it uses as much as digits as its factorization.
1123433230201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1123433230201 its reverse (1020323343211), we get a palindrome (2143756573412).
The spelling of 1123433230201 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-three million, two hundred thirty thousand, two hundred one".
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