112343330122241 has 4 divisors (see below), whose sum is σ = 118256136970800. Its totient is φ = 106430523273684.

The previous prime is 112343330122223. The next prime is 112343330122313. The reversal of 112343330122241 is 142221033343211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112343330122241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112343330122198 and 112343330122207.

It is not an unprimeable number, because it can be changed into a prime (112343330122201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2956403424251 + ... + 2956403424288.

It is an arithmetic number, because the mean of its divisors is an integer number (29564034242700).

Almost surely, 2^{112343330122241} is an apocalyptic number.

It is an amenable number.

112343330122241 is a deficient number, since it is larger than the sum of its proper divisors (5912806848559).

112343330122241 is an equidigital number, since it uses as much as digits as its factorization.

112343330122241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5912806848558.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 112343330122241 its reverse (142221033343211), we get a palindrome (254564363465452).

The spelling of 112343330122241 in words is "one hundred twelve trillion, three hundred forty-three billion, three hundred thirty million, one hundred twenty-two thousand, two hundred forty-one".