11234340433 has 4 divisors (see below), whose sum is σ = 11495604208. Its totient is φ = 10973076660.

The previous prime is 11234340419. The next prime is 11234340443. The reversal of 11234340433 is 33404343211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33404343211 = 89 ⋅375329699.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11234340433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11234340413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130631823 + ... + 130631908.

It is an arithmetic number, because the mean of its divisors is an integer number (2873901052).

Almost surely, 2^11234340433 is an apocalyptic number.

It is an amenable number.

11234340433 is a deficient number, since it is larger than the sum of its proper divisors (261263775).

11234340433 is an equidigital number, since it uses as much as digits as its factorization.

11234340433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261263774.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 11234340433 its reverse (33404343211), we get a palindrome (44638683644).

The spelling of 11234340433 in words is "eleven billion, two hundred thirty-four million, three hundred forty thousand, four hundred thirty-three".