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11234441413051 is a prime number
BaseRepresentation
bin1010001101111011100011…
…1000111100000110111011
31110210000001112112102111121
42203132320320330012323
52433031114000204201
635521010420410111
72236442634256303
oct243367070740673
943700045472447
1011234441413051
11364155532953a
121315387846937
1363653200b07c
142aba6d8ba603
151473786219a1
hexa37b8e3c1bb

11234441413051 has 2 divisors, whose sum is σ = 11234441413052. Its totient is φ = 11234441413050.

The previous prime is 11234441413033. The next prime is 11234441413067. The reversal of 11234441413051 is 15031414443211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11234441413051 - 29 = 11234441412539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11234441412998 and 11234441413016.

It is not a weakly prime, because it can be changed into another prime (11234441411051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617220706525 + 5617220706526.

It is an arithmetic number, because the mean of its divisors is an integer number (5617220706526).

Almost surely, 211234441413051 is an apocalyptic number.

11234441413051 is a deficient number, since it is larger than the sum of its proper divisors (1).

11234441413051 is an equidigital number, since it uses as much as digits as its factorization.

11234441413051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 11234441413051 its reverse (15031414443211), we get a palindrome (26265855856262).

The spelling of 11234441413051 in words is "eleven trillion, two hundred thirty-four billion, four hundred forty-one million, four hundred thirteen thousand, fifty-one".