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11235311013434 = 243130643151319
BaseRepresentation
bin1010001101111110110010…
…1110001100111000111010
31110210002022010211200222012
42203133230232030320322
52433034404104412214
635521233003125522
72236503323613344
oct243375456147072
943702263750865
1011235311013434
113641961188142
12131558ab138a2
1363664021c901
142abb131a2294
151473c9b4603e
hexa37ecb8ce3a

11235311013434 has 8 divisors (see below), whose sum is σ = 17244895974240. Its totient is φ = 5487012355356.

The previous prime is 11235311013427. The next prime is 11235311013463. The reversal of 11235311013434 is 43431011353211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×112353110134342 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11235311013434.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65321575574 + ... + 65321575745.

It is an arithmetic number, because the mean of its divisors is an integer number (2155611996780).

Almost surely, 211235311013434 is an apocalyptic number.

11235311013434 is a deficient number, since it is larger than the sum of its proper divisors (6009584960806).

11235311013434 is a wasteful number, since it uses less digits than its factorization.

11235311013434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 130643151364.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 11235311013434 its reverse (43431011353211), we get a palindrome (54666322366645).

The spelling of 11235311013434 in words is "eleven trillion, two hundred thirty-five billion, three hundred eleven million, thirteen thousand, four hundred thirty-four".

Divisors: 1 2 43 86 130643151319 261286302638 5617655506717 11235311013434