Base | Representation |
---|---|
bin | 10000010110011110111… |
… | …000110111100011100001 |
3 | 10222102100020210121010011 |
4 | 100112132320313203201 |
5 | 121402214424001001 |
6 | 2220110525404521 |
7 | 144116101605142 |
oct | 20263670674341 |
9 | 3872306717104 |
10 | 1123652172001 |
11 | 3a35a13a2987 |
12 | 161930a09741 |
13 | 81c62ccbc18 |
14 | 3c55683dac9 |
15 | 1e367186d51 |
hex | 1059ee378e1 |
1123652172001 has 2 divisors, whose sum is σ = 1123652172002. Its totient is φ = 1123652172000.
The previous prime is 1123652171989. The next prime is 1123652172061. The reversal of 1123652172001 is 1002712563211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1088733643776 + 34918528225 = 1043424^2 + 186865^2 .
It is an emirp because it is prime and its reverse (1002712563211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1123652172001 - 25 = 1123652171969 is a prime.
It is not a weakly prime, because it can be changed into another prime (1123652172061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561826086000 + 561826086001.
It is an arithmetic number, because the mean of its divisors is an integer number (561826086001).
Almost surely, 21123652172001 is an apocalyptic number.
It is an amenable number.
1123652172001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123652172001 is an equidigital number, since it uses as much as digits as its factorization.
1123652172001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 31.
The spelling of 1123652172001 in words is "one trillion, one hundred twenty-three billion, six hundred fifty-two million, one hundred seventy-two thousand, one".
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