Base | Representation |
---|---|
bin | 11001100011101000101100… |
… | …101100100000010000101110 |
3 | 112201222100011022202110010210 |
4 | 121203220230230200100232 |
5 | 104213030242231002202 |
6 | 1035015511204043250 |
7 | 32450430605104452 |
oct | 3143505454402056 |
9 | 481870138673123 |
10 | 112400044000302 |
11 | 328a5655636463 |
12 | 10733a6b393526 |
13 | 4a9438130b436 |
14 | 1da8296768662 |
15 | cedbb2dcac6c |
hex | 663a2cb2042e |
112400044000302 has 16 divisors (see below), whose sum is σ = 227508522796800. Its totient is φ = 37015275534072.
The previous prime is 112400044000297. The next prime is 112400044000303. The reversal of 112400044000302 is 203000440004211.
112400044000302 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112400044000303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 112851449302 + ... + 112851450297.
It is an arithmetic number, because the mean of its divisors is an integer number (14219282674800).
Almost surely, 2112400044000302 is an apocalyptic number.
112400044000302 is an abundant number, since it is smaller than the sum of its proper divisors (115108478796498).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112400044000302 is a wasteful number, since it uses less digits than its factorization.
112400044000302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 225702899687.
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 112400044000302 its reverse (203000440004211), we get a palindrome (315400484004513).
The spelling of 112400044000302 in words is "one hundred twelve trillion, four hundred billion, forty-four million, three hundred two", and thus it is an aban number.
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