Base | Representation |
---|---|
bin | 10100111100000010… |
… | …11001001101010001 |
3 | 1002000102010001102020 |
4 | 22132001121031101 |
5 | 141010210200423 |
6 | 5055235442053 |
7 | 545364526425 |
oct | 123601311521 |
9 | 32012101366 |
10 | 11241100113 |
11 | 4849342991 |
12 | 2218756329 |
13 | 10a1b72139 |
14 | 788d10b85 |
15 | 45bd164e3 |
hex | 29e059351 |
11241100113 has 8 divisors (see below), whose sum is σ = 14989144800. Its totient is φ = 7493561088.
The previous prime is 11241100081. The next prime is 11241100127. The reversal of 11241100113 is 31100114211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11241100113 - 25 = 11241100081 is a prime.
It is a super-2 number, since 2×112411001132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11241100092 and 11241100101.
It is not an unprimeable number, because it can be changed into a prime (11241100613) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71083 + ... + 165936.
It is an arithmetic number, because the mean of its divisors is an integer number (1873643100).
Almost surely, 211241100113 is an apocalyptic number.
It is an amenable number.
11241100113 is a deficient number, since it is larger than the sum of its proper divisors (3748044687).
11241100113 is a wasteful number, since it uses less digits than its factorization.
11241100113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 252831.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11241100113 its reverse (31100114211), we get a palindrome (42341214324).
The spelling of 11241100113 in words is "eleven billion, two hundred forty-one million, one hundred thousand, one hundred thirteen".
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