11241135214433 has 4 divisors (see below), whose sum is σ = 11241165382320. Its totient is φ = 11241105046548.

The previous prime is 11241135214403. The next prime is 11241135214451. The reversal of 11241135214433 is 33441253114211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11241135214433 - 2¹² = 11241135210337 is a prime.

It is a super-2 number, since 2×11241135214433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11241135214393 and 11241135214402.

It is not an unprimeable number, because it can be changed into a prime (11241135214403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14517935 + ... + 15272612.

It is an arithmetic number, because the mean of its divisors is an integer number (2810291345580).

Almost surely, 2^{11241135214433} is an apocalyptic number.

It is an amenable number.

11241135214433 is a deficient number, since it is larger than the sum of its proper divisors (30167887).

11241135214433 is an equidigital number, since it uses as much as digits as its factorization.

11241135214433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30167886.

The product of its digits is 34560, while the sum is 35.

Adding to 11241135214433 its reverse (33441253114211), we get a palindrome (44682388328644).

The spelling of 11241135214433 in words is "eleven trillion, two hundred forty-one billion, one hundred thirty-five million, two hundred fourteen thousand, four hundred thirty-three".