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112414015122113 is a prime number
BaseRepresentation
bin11001100011110101101101…
…011100000110101011000001
3112202000200012222212222021202
4121203311231130012223001
5104213242400332401423
61035030141405430545
732451434042506145
oct3143655534065301
9482020188788252
10112414015122113
1132900574a00021
121073670a26b455
134a95799948b13
141da8c20085225
15cee22e707728
hex663d6d706ac1

112414015122113 has 2 divisors, whose sum is σ = 112414015122114. Its totient is φ = 112414015122112.

The previous prime is 112414015122109. The next prime is 112414015122163. The reversal of 112414015122113 is 311221510414211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112346284018609 + 67731103504 = 10599353^2 + 260252^2 .

It is an emirp because it is prime and its reverse (311221510414211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112414015122113 - 22 = 112414015122109 is a prime.

It is not a weakly prime, because it can be changed into another prime (112414015122163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56207007561056 + 56207007561057.

It is an arithmetic number, because the mean of its divisors is an integer number (56207007561057).

Almost surely, 2112414015122113 is an apocalyptic number.

It is an amenable number.

112414015122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112414015122113 is an equidigital number, since it uses as much as digits as its factorization.

112414015122113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 29.

Adding to 112414015122113 its reverse (311221510414211), we get a palindrome (423635525536324).

The spelling of 112414015122113 in words is "one hundred twelve trillion, four hundred fourteen billion, fifteen million, one hundred twenty-two thousand, one hundred thirteen".