Base | Representation |
---|---|
bin | 10000010111000000010… |
… | …101110101011001101011 |
3 | 10222110210100212121200201 |
4 | 100113000111311121223 |
5 | 121404342113212413 |
6 | 2220242335013031 |
7 | 144136025226526 |
oct | 20270025653153 |
9 | 3873710777621 |
10 | 1124213413483 |
11 | 3a385a188a16 |
12 | 161a6896a177 |
13 | 82022377084 |
14 | 3c5ab1b7bbd |
15 | 1e39b59a9dd |
hex | 105c057566b |
1124213413483 has 2 divisors, whose sum is σ = 1124213413484. Its totient is φ = 1124213413482.
The previous prime is 1124213413471. The next prime is 1124213413487. The reversal of 1124213413483 is 3843143124211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1124213413483 - 237 = 986774460011 is a prime.
It is not a weakly prime, because it can be changed into another prime (1124213413487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562106706741 + 562106706742.
It is an arithmetic number, because the mean of its divisors is an integer number (562106706742).
Almost surely, 21124213413483 is an apocalyptic number.
1124213413483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124213413483 is an equidigital number, since it uses as much as digits as its factorization.
1124213413483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 55296, while the sum is 37.
Adding to 1124213413483 its reverse (3843143124211), we get a palindrome (4967356537694).
The spelling of 1124213413483 in words is "one trillion, one hundred twenty-four billion, two hundred thirteen million, four hundred thirteen thousand, four hundred eighty-three".
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