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112431323040313 is a prime number
BaseRepresentation
bin11001100100000101110101…
…000100100100101000111001
3112202002022220012210022120011
4121210011311010210220321
5104214033322144242223
61035042123050301521
732452615665416104
oct3144056504445071
9482068805708504
10112431323040313
1132907946861152
1210739b3a7278a1
134a972c7680134
141da99c29d973b
15cee8e3e5480d
hex664175124a39

112431323040313 has 2 divisors, whose sum is σ = 112431323040314. Its totient is φ = 112431323040312.

The previous prime is 112431323040221. The next prime is 112431323040329. The reversal of 112431323040313 is 313040323134211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77472862685689 + 34958460354624 = 8801867^2 + 5912568^2 .

It is an emirp because it is prime and its reverse (313040323134211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112431323040313 is a prime.

It is not a weakly prime, because it can be changed into another prime (112431323041313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56215661520156 + 56215661520157.

It is an arithmetic number, because the mean of its divisors is an integer number (56215661520157).

Almost surely, 2112431323040313 is an apocalyptic number.

It is an amenable number.

112431323040313 is a deficient number, since it is larger than the sum of its proper divisors (1).

112431323040313 is an equidigital number, since it uses as much as digits as its factorization.

112431323040313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 112431323040313 its reverse (313040323134211), we get a palindrome (425471646174524).

The spelling of 112431323040313 in words is "one hundred twelve trillion, four hundred thirty-one billion, three hundred twenty-three million, forty thousand, three hundred thirteen".